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13011985627423 is a prime number
BaseRepresentation
bin1011110101011001011011…
…0001111111100100011111
31201001221012122120111011021
42331112112301333210133
53201142021310034143
643401342414105011
72512041063634516
oct275262661774437
951057178514137
1013011985627423
114167396735002
1215619877ab167
13735042b5a053
1432dad7b8167d
15178711a18ced
hexbd596c7f91f

13011985627423 has 2 divisors, whose sum is σ = 13011985627424. Its totient is φ = 13011985627422.

The previous prime is 13011985627339. The next prime is 13011985627427. The reversal of 13011985627423 is 32472658911031.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13011985627423 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13011985627427) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6505992813711 + 6505992813712.

It is an arithmetic number, because the mean of its divisors is an integer number (6505992813712).

It is a 2-persistent number, because it is pandigital, and so is 2⋅13011985627423 = 26023971254846, but 3⋅13011985627423 = 39035956882269 is not.

Almost surely, 213011985627423 is an apocalyptic number.

13011985627423 is a deficient number, since it is larger than the sum of its proper divisors (1).

13011985627423 is an equidigital number, since it uses as much as digits as its factorization.

13011985627423 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2177280, while the sum is 52.

The spelling of 13011985627423 in words is "thirteen trillion, eleven billion, nine hundred eighty-five million, six hundred twenty-seven thousand, four hundred twenty-three".