Base | Representation |
---|---|
bin | 1011110101011001011011… |
… | …0001111111100100011111 |
3 | 1201001221012122120111011021 |
4 | 2331112112301333210133 |
5 | 3201142021310034143 |
6 | 43401342414105011 |
7 | 2512041063634516 |
oct | 275262661774437 |
9 | 51057178514137 |
10 | 13011985627423 |
11 | 4167396735002 |
12 | 15619877ab167 |
13 | 735042b5a053 |
14 | 32dad7b8167d |
15 | 178711a18ced |
hex | bd596c7f91f |
13011985627423 has 2 divisors, whose sum is σ = 13011985627424. Its totient is φ = 13011985627422.
The previous prime is 13011985627339. The next prime is 13011985627427. The reversal of 13011985627423 is 32472658911031.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13011985627423 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13011985627427) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6505992813711 + 6505992813712.
It is an arithmetic number, because the mean of its divisors is an integer number (6505992813712).
It is a 2-persistent number, because it is pandigital, and so is 2⋅13011985627423 = 26023971254846, but 3⋅13011985627423 = 39035956882269 is not.
Almost surely, 213011985627423 is an apocalyptic number.
13011985627423 is a deficient number, since it is larger than the sum of its proper divisors (1).
13011985627423 is an equidigital number, since it uses as much as digits as its factorization.
13011985627423 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2177280, while the sum is 52.
The spelling of 13011985627423 in words is "thirteen trillion, eleven billion, nine hundred eighty-five million, six hundred twenty-seven thousand, four hundred twenty-three".
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