Base | Representation |
---|---|
bin | 111100100101111000… |
… | …1001011011100011011 |
3 | 110102212022010010210011 |
4 | 1321023301023130123 |
5 | 4112441232431021 |
6 | 135435411302351 |
7 | 12254333316352 |
oct | 1711361133433 |
9 | 412768103704 |
10 | 130120202011 |
11 | 50202509738 |
12 | 21274baa9b7 |
13 | c368a6c697 |
14 | 6425438999 |
15 | 35b86a8de1 |
hex | 1e4bc4b71b |
130120202011 has 2 divisors, whose sum is σ = 130120202012. Its totient is φ = 130120202010.
The previous prime is 130120201999. The next prime is 130120202021. The reversal of 130120202011 is 110202021031.
It is a strong prime.
It is an emirp because it is prime and its reverse (110202021031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 130120202011 - 217 = 130120070939 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 130120201982 and 130120202000.
It is not a weakly prime, because it can be changed into another prime (130120202021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65060101005 + 65060101006.
It is an arithmetic number, because the mean of its divisors is an integer number (65060101006).
Almost surely, 2130120202011 is an apocalyptic number.
130120202011 is a deficient number, since it is larger than the sum of its proper divisors (1).
130120202011 is an equidigital number, since it uses as much as digits as its factorization.
130120202011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 130120202011 its reverse (110202021031), we get a palindrome (240322223042).
The spelling of 130120202011 in words is "one hundred thirty billion, one hundred twenty million, two hundred two thousand, eleven".
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