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13012024424309 is a prime number
BaseRepresentation
bin1011110101011001100100…
…0101111111011101110101
31201001221022100120120110222
42331112121011333131311
53201142111223034214
643401350321424125
72512042044462131
oct275263105773565
951057270516428
1013012024424309
114167406623749
12156199879b045
1373504abc20a1
1432dadcda03c1
1517871512e38e
hexbd59917f775

13012024424309 has 2 divisors, whose sum is σ = 13012024424310. Its totient is φ = 13012024424308.

The previous prime is 13012024424261. The next prime is 13012024424317. The reversal of 13012024424309 is 90342442021031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8340093478084 + 4671930946225 = 2887922^2 + 2161465^2 .

It is an emirp because it is prime and its reverse (90342442021031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13012024424309 - 232 = 13007729457013 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13012024421309) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6506012212154 + 6506012212155.

It is an arithmetic number, because the mean of its divisors is an integer number (6506012212155).

Almost surely, 213012024424309 is an apocalyptic number.

It is an amenable number.

13012024424309 is a deficient number, since it is larger than the sum of its proper divisors (1).

13012024424309 is an equidigital number, since it uses as much as digits as its factorization.

13012024424309 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 41472, while the sum is 35.

The spelling of 13012024424309 in words is "thirteen trillion, twelve billion, twenty-four million, four hundred twenty-four thousand, three hundred nine".