Base | Representation |
---|---|
bin | 10010111011110101110… |
… | …100001001100100110110 |
3 | 11121101122011021202120102 |
4 | 102323311310021210312 |
5 | 132304331234241042 |
6 | 2433433122034102 |
7 | 163003024211531 |
oct | 22736564114466 |
9 | 4541564252512 |
10 | 1301204212022 |
11 | 461923945540 |
12 | 1902227a8932 |
13 | 9591a734b30 |
14 | 46d9b493a18 |
15 | 23ca99e3b32 |
hex | 12ef5d09936 |
1301204212022 has 32 divisors (see below), whose sum is σ = 2355005034144. Its totient is φ = 531204134400.
The previous prime is 1301204212001. The next prime is 1301204212081. The reversal of 1301204212022 is 2202124021031.
It is a super-3 number, since 3×13012042120223 (a number of 37 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1301204211985 and 1301204212003.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 61471379 + ... + 61492542.
It is an arithmetic number, because the mean of its divisors is an integer number (73593907317).
Almost surely, 21301204212022 is an apocalyptic number.
1301204212022 is a deficient number, since it is larger than the sum of its proper divisors (1053800822122).
1301204212022 is a wasteful number, since it uses less digits than its factorization.
1301204212022 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 122963984.
The product of its (nonzero) digits is 384, while the sum is 20.
Adding to 1301204212022 its reverse (2202124021031), we get a palindrome (3503328233053).
The spelling of 1301204212022 in words is "one trillion, three hundred one billion, two hundred four million, two hundred twelve thousand, twenty-two".
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