Base | Representation |
---|---|
bin | 10010111011110110001… |
… | …010100111000110011001 |
3 | 11121101122120100220112011 |
4 | 102323312022213012121 |
5 | 132304334241200441 |
6 | 2433433452145521 |
7 | 163003125234151 |
oct | 22736612470631 |
9 | 4541576326464 |
10 | 1301210100121 |
11 | 4619271a7338 |
12 | 1902247682a1 |
13 | 9591ba16c09 |
14 | 46d9c187761 |
15 | 23caa2a8581 |
hex | 12ef62a7199 |
1301210100121 has 2 divisors, whose sum is σ = 1301210100122. Its totient is φ = 1301210100120.
The previous prime is 1301210100103. The next prime is 1301210100131. The reversal of 1301210100121 is 1210010121031.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1170267440521 + 130942659600 = 1081789^2 + 361860^2 .
It is a cyclic number.
It is not a de Polignac number, because 1301210100121 - 211 = 1301210098073 is a prime.
It is not a weakly prime, because it can be changed into another prime (1301210100101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650605050060 + 650605050061.
It is an arithmetic number, because the mean of its divisors is an integer number (650605050061).
Almost surely, 21301210100121 is an apocalyptic number.
It is an amenable number.
1301210100121 is a deficient number, since it is larger than the sum of its proper divisors (1).
1301210100121 is an equidigital number, since it uses as much as digits as its factorization.
1301210100121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12, while the sum is 13.
Adding to 1301210100121 its reverse (1210010121031), we get a palindrome (2511220221152).
The spelling of 1301210100121 in words is "one trillion, three hundred one billion, two hundred ten million, one hundred thousand, one hundred twenty-one".
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