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1301212131000 = 233531990725169
BaseRepresentation
bin10010111011110110010…
…010010110111010111000
311121101122201012002100220
4102323312102112322320
5132304340301143000
62433434003500040
7163003151423115
oct22736622267270
94541581162326
101301212131000
11461928364151
12190225387620
139591c278412
1446d9c55590c
1523caa55a1a0
hex12ef6496eb8

1301212131000 has 256 divisors, whose sum is σ = 4278336192000. Its totient is φ = 328351795200.

The previous prime is 1301212130989. The next prime is 1301212131013. The reversal of 1301212131000 is 1312121031.

It is a happy number.

It is a super-2 number, since 2×13012121310002 (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 51686416 + ... + 51711584.

It is an arithmetic number, because the mean of its divisors is an integer number (16712250750).

Almost surely, 21301212131000 is an apocalyptic number.

1301212131000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1301212131000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2139168096000).

1301212131000 is an abundant number, since it is smaller than the sum of its proper divisors (2977124061000).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1301212131000 is a wasteful number, since it uses less digits than its factorization.

1301212131000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26119 (or 26105 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 1301212131000 its reverse (1312121031), we get a palindrome (1302524252031).

The spelling of 1301212131000 in words is "one trillion, three hundred one billion, two hundred twelve million, one hundred thirty-one thousand".