Search a number
-
+
130122213112393 is a prime number
BaseRepresentation
bin11101100101100001110000…
…010010100011101001001001
3122001201120011202112122201221
4131211201300102203221021
5114023410243024044033
61140425153001042041
736260006513054545
oct3545416022435111
9561646152478657
10130122213112393
1138508580028457
1212716681a86321
13577b61a1122c8
14241bd3d3d6a25
151009b9d9ab12d
hex7658704a3a49

130122213112393 has 2 divisors, whose sum is σ = 130122213112394. Its totient is φ = 130122213112392.

The previous prime is 130122213112249. The next prime is 130122213112481. The reversal of 130122213112393 is 393211312221031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 109323168115984 + 20799044996409 = 10455772^2 + 4560597^2 .

It is an emirp because it is prime and its reverse (393211312221031) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130122213112393 is a prime.

It is not a weakly prime, because it can be changed into another prime (130122213142393) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65061106556196 + 65061106556197.

It is an arithmetic number, because the mean of its divisors is an integer number (65061106556197).

Almost surely, 2130122213112393 is an apocalyptic number.

It is an amenable number.

130122213112393 is a deficient number, since it is larger than the sum of its proper divisors (1).

130122213112393 is an equidigital number, since it uses as much as digits as its factorization.

130122213112393 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 11664, while the sum is 34.

The spelling of 130122213112393 in words is "one hundred thirty trillion, one hundred twenty-two billion, two hundred thirteen million, one hundred twelve thousand, three hundred ninety-three".