Base | Representation |
---|---|
bin | 10010111011110111011… |
… | …011001001001001111100 |
3 | 11121101201001002110101110 |
4 | 102323313123021021330 |
5 | 132304410142224012 |
6 | 2433435524442020 |
7 | 163003502541246 |
oct | 22736733111174 |
9 | 4541631073343 |
10 | 1301231211132 |
11 | 461938106356 |
12 | 19022b849310 |
13 | 959231c8c38 |
14 | 46da0cc1096 |
15 | 23cac07873c |
hex | 12ef76c927c |
1301231211132 has 24 divisors (see below), whose sum is σ = 3077798026576. Its totient is φ = 427802041728.
The previous prime is 1301231211121. The next prime is 1301231211143. The reversal of 1301231211132 is 2311121321031.
It is an interprime number because it is at equal distance from previous prime (1301231211121) and next prime (1301231211143).
It is a junction number, because it is equal to n+sod(n) for n = 1301231211099 and 1301231211108.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 742711003 + ... + 742712754.
Almost surely, 21301231211132 is an apocalyptic number.
1301231211132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
1301231211132 is an abundant number, since it is smaller than the sum of its proper divisors (1776566815444).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1301231211132 is a wasteful number, since it uses less digits than its factorization.
1301231211132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1485423837 (or 1485423835 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 21.
Adding to 1301231211132 its reverse (2311121321031), we get a palindrome (3612352532163).
The spelling of 1301231211132 in words is "one trillion, three hundred one billion, two hundred thirty-one million, two hundred eleven thousand, one hundred thirty-two".
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