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130123548253 = 771671686259
BaseRepresentation
bin111100100101111110…
…1111100011001011101
3110102212112102010222001
41321023331330121131
54112443112021003
6135440011122301
712254403624226
oct1711375743135
9412775363861
10130123548253
1150204394826
1221276143391
13c3696717ca
146425a6a24d
1535b8b1a61d
hex1e4bf7c65d

130123548253 has 4 divisors (see below), whose sum is σ = 130125311680. Its totient is φ = 130121784828.

The previous prime is 130123548221. The next prime is 130123548293. The reversal of 130123548253 is 352845321031.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 130123548253 - 25 = 130123548221 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130123548293) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 765963 + ... + 920296.

It is an arithmetic number, because the mean of its divisors is an integer number (32531327920).

Almost surely, 2130123548253 is an apocalyptic number.

It is an amenable number.

130123548253 is a deficient number, since it is larger than the sum of its proper divisors (1763427).

130123548253 is an equidigital number, since it uses as much as digits as its factorization.

130123548253 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1763426.

The product of its (nonzero) digits is 86400, while the sum is 37.

Adding to 130123548253 its reverse (352845321031), we get a palindrome (482968869284).

The spelling of 130123548253 in words is "one hundred thirty billion, one hundred twenty-three million, five hundred forty-eight thousand, two hundred fifty-three".

Divisors: 1 77167 1686259 130123548253