Base | Representation |
---|---|
bin | 111100100101111110… |
… | …1111100011010000101 |
3 | 110102212112102011000112 |
4 | 1321023331330122011 |
5 | 4112443112021133 |
6 | 135440011122405 |
7 | 12254403624314 |
oct | 1711375743205 |
9 | 412775364015 |
10 | 130123548293 |
11 | 50204394862 |
12 | 21276143405 |
13 | c36967182b |
14 | 6425a6a27b |
15 | 35b8b1a648 |
hex | 1e4bf7c685 |
130123548293 has 2 divisors, whose sum is σ = 130123548294. Its totient is φ = 130123548292.
The previous prime is 130123548221. The next prime is 130123548301. The reversal of 130123548293 is 392845321031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 119870365729 + 10253182564 = 346223^2 + 101258^2 .
It is a cyclic number.
It is not a de Polignac number, because 130123548293 - 218 = 130123286149 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 130123548293.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130123578293) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65061774146 + 65061774147.
It is an arithmetic number, because the mean of its divisors is an integer number (65061774147).
Almost surely, 2130123548293 is an apocalyptic number.
It is an amenable number.
130123548293 is a deficient number, since it is larger than the sum of its proper divisors (1).
130123548293 is an equidigital number, since it uses as much as digits as its factorization.
130123548293 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 155520, while the sum is 41.
The spelling of 130123548293 in words is "one hundred thirty billion, one hundred twenty-three million, five hundred forty-eight thousand, two hundred ninety-three".
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