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130125044581853 is a prime number
BaseRepresentation
bin11101100101100100011001…
…000011110000010111011101
3122001201211111002110012122012
4131211210121003300113131
5114023432042403104403
61140430341545201005
736260136624131546
oct3545443103602735
9561654432405565
10130125044581853
11385097a334a362
1212717132190165
13577b97b90a319
14241c12b48d4cd
151009cb735eed8
hex7659190f05dd

130125044581853 has 2 divisors, whose sum is σ = 130125044581854. Its totient is φ = 130125044581852.

The previous prime is 130125044581849. The next prime is 130125044581921. The reversal of 130125044581853 is 358185440521031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 75280385486329 + 54844659095524 = 8676427^2 + 7405718^2 .

It is a cyclic number.

It is not a de Polignac number, because 130125044581853 - 22 = 130125044581849 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130125044584853) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65062522290926 + 65062522290927.

It is an arithmetic number, because the mean of its divisors is an integer number (65062522290927).

Almost surely, 2130125044581853 is an apocalyptic number.

It is an amenable number.

130125044581853 is a deficient number, since it is larger than the sum of its proper divisors (1).

130125044581853 is an equidigital number, since it uses as much as digits as its factorization.

130125044581853 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304000, while the sum is 50.

The spelling of 130125044581853 in words is "one hundred thirty trillion, one hundred twenty-five billion, forty-four million, five hundred eighty-one thousand, eight hundred fifty-three".