Base | Representation |
---|---|
bin | 11000001111001101… |
… | …10111100011111111 |
3 | 1020120212101002101110 |
4 | 30013212313203333 |
5 | 203122202001310 |
6 | 5551115413103 |
7 | 640314456330 |
oct | 140746674377 |
9 | 36525332343 |
10 | 13012531455 |
11 | 5578264530 |
12 | 2631a54193 |
13 | 12c4b6b871 |
14 | 8b62ac287 |
15 | 5125c9d20 |
hex | 3079b78ff |
13012531455 has 64 divisors (see below), whose sum is σ = 26129719296. Its totient is φ = 5371920000.
The previous prime is 13012531453. The next prime is 13012531481. The reversal of 13012531455 is 55413521031.
It is not a de Polignac number, because 13012531455 - 21 = 13012531453 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13012531453) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 137100 + ... + 211710.
It is an arithmetic number, because the mean of its divisors is an integer number (408276864).
Almost surely, 213012531455 is an apocalyptic number.
13012531455 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13012531455 is an abundant number, since it is smaller than the sum of its proper divisors (13117187841).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13012531455 is a wasteful number, since it uses less digits than its factorization.
13012531455 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 74788.
The product of its (nonzero) digits is 9000, while the sum is 30.
The spelling of 13012531455 in words is "thirteen billion, twelve million, five hundred thirty-one thousand, four hundred fifty-five".
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