Base | Representation |
---|---|
bin | 11101100101100101110000… |
… | …010000000001010011000011 |
3 | 122001201222021001000211002101 |
4 | 131211211300100001103003 |
5 | 114023443041344232343 |
6 | 1140431143042531231 |
7 | 36260221106040451 |
oct | 3545456020012303 |
9 | 561658231024071 |
10 | 130126507414723 |
11 | 3850a384054346 |
12 | 12717480066b17 |
13 | 577bb529b82c1 |
14 | 241c2298799d1 |
15 | 1009d509b6e4d |
hex | 7659704014c3 |
130126507414723 has 2 divisors, whose sum is σ = 130126507414724. Its totient is φ = 130126507414722.
The previous prime is 130126507414721. The next prime is 130126507414741. The reversal of 130126507414723 is 327414705621031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 130126507414723 - 21 = 130126507414721 is a prime.
Together with 130126507414721, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (130126507414721) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65063253707361 + 65063253707362.
It is an arithmetic number, because the mean of its divisors is an integer number (65063253707362).
Almost surely, 2130126507414723 is an apocalyptic number.
130126507414723 is a deficient number, since it is larger than the sum of its proper divisors (1).
130126507414723 is an equidigital number, since it uses as much as digits as its factorization.
130126507414723 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 846720, while the sum is 46.
The spelling of 130126507414723 in words is "one hundred thirty trillion, one hundred twenty-six billion, five hundred seven million, four hundred fourteen thousand, seven hundred twenty-three".
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