1301279638450 has 48 divisors (see below), whose sum is σ = 2657901044160. Its totient is φ = 470058840000.

The previous prime is 1301279638427. The next prime is 1301279638457. The reversal of 1301279638450 is 548369721031.

It is a junction number, because it is equal to n+sod(n) for n = 1301279638394 and 1301279638403.

It is not an unprimeable number, because it can be changed into a prime (1301279638457) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 7751265 + ... + 7917364.

It is an arithmetic number, because the mean of its divisors is an integer number (55372938420).

It is a 1-persistent number, because it is pandigital, but 2⋅1301279638450 = 2602559276900 is not.

Almost surely, 2^{1301279638450} is an apocalyptic number.

1301279638450 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1301279638450 is an abundant number, since it is smaller than the sum of its proper divisors (1356621405710).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1301279638450 is a wasteful number, since it uses less digits than its factorization.

1301279638450 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15668803 (or 15668798 counting only the distinct ones).

The product of its (nonzero) digits is 1088640, while the sum is 49.

The spelling of 1301279638450 in words is "one trillion, three hundred one billion, two hundred seventy-nine million, six hundred thirty-eight thousand, four hundred fifty".