Base | Representation |
---|---|
bin | 1011110101011101001100… |
… | …1111111100100000101101 |
3 | 1201002000211100111122121112 |
4 | 2331113103033330200231 |
5 | 3201201111012042143 |
6 | 43402031214041405 |
7 | 2512105162624145 |
oct | 275272317744055 |
9 | 51060740448545 |
10 | 13013000112173 |
11 | 4167867351456 |
12 | 156200b4a9265 |
13 | 735175099199 |
14 | 32db927bd925 |
15 | 178770b0be18 |
hex | bd5d33fc82d |
13013000112173 has 2 divisors, whose sum is σ = 13013000112174. Its totient is φ = 13013000112172.
The previous prime is 13013000112163. The next prime is 13013000112221. The reversal of 13013000112173 is 37121100031031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12384473028964 + 628527083209 = 3519158^2 + 792797^2 .
It is an emirp because it is prime and its reverse (37121100031031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13013000112173 - 210 = 13013000111149 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13013000112103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6506500056086 + 6506500056087.
It is an arithmetic number, because the mean of its divisors is an integer number (6506500056087).
Almost surely, 213013000112173 is an apocalyptic number.
It is an amenable number.
13013000112173 is a deficient number, since it is larger than the sum of its proper divisors (1).
13013000112173 is an equidigital number, since it uses as much as digits as its factorization.
13013000112173 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 378, while the sum is 23.
The spelling of 13013000112173 in words is "thirteen trillion, thirteen billion, one hundred twelve thousand, one hundred seventy-three".
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