Base | Representation |
---|---|
bin | 11000001111010010… |
… | …00110110000011101 |
3 | 1020120220110212221122 |
4 | 30013221012300131 |
5 | 203122324233411 |
6 | 5551140140325 |
7 | 640322451323 |
oct | 140751066035 |
9 | 36526425848 |
10 | 13013117981 |
11 | 5578625166 |
12 | 26320976a5 |
13 | 12c5015816 |
14 | 8b63c1d13 |
15 | 5126939db |
hex | 307a46c1d |
13013117981 has 2 divisors, whose sum is σ = 13013117982. Its totient is φ = 13013117980.
The previous prime is 13013117977. The next prime is 13013118017. The reversal of 13013117981 is 18971131031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12208261081 + 804856900 = 110491^2 + 28370^2 .
It is an emirp because it is prime and its reverse (18971131031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13013117981 - 22 = 13013117977 is a prime.
It is a super-2 number, since 2×130131179812 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13013117911) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6506558990 + 6506558991.
It is an arithmetic number, because the mean of its divisors is an integer number (6506558991).
Almost surely, 213013117981 is an apocalyptic number.
It is an amenable number.
13013117981 is a deficient number, since it is larger than the sum of its proper divisors (1).
13013117981 is an equidigital number, since it uses as much as digits as its factorization.
13013117981 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4536, while the sum is 35.
The spelling of 13013117981 in words is "thirteen billion, thirteen million, one hundred seventeen thousand, nine hundred eighty-one".
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