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13013124401317 is a prime number
BaseRepresentation
bin1011110101011101101010…
…1010000100100010100101
31201002001011000101012021011
42331113122222010202211
53201201334321320232
643402051414022221
72512111232231155
oct275273252044245
951061130335234
1013013124401317
114167920522757
121562045047971
13735194a65461
1432dba50d4765
1517877b9ad547
hexbd5daa848a5

13013124401317 has 2 divisors, whose sum is σ = 13013124401318. Its totient is φ = 13013124401316.

The previous prime is 13013124401131. The next prime is 13013124401353. The reversal of 13013124401317 is 71310442131031.

13013124401317 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12943200647556 + 69923753761 = 3597666^2 + 264431^2 .

It is a cyclic number.

It is not a de Polignac number, because 13013124401317 - 215 = 13013124368549 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13013124401917) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6506562200658 + 6506562200659.

It is an arithmetic number, because the mean of its divisors is an integer number (6506562200659).

Almost surely, 213013124401317 is an apocalyptic number.

It is an amenable number.

13013124401317 is a deficient number, since it is larger than the sum of its proper divisors (1).

13013124401317 is an equidigital number, since it uses as much as digits as its factorization.

13013124401317 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6048, while the sum is 31.

Adding to 13013124401317 its reverse (71310442131031), we get a palindrome (84323566532348).

The spelling of 13013124401317 in words is "thirteen trillion, thirteen billion, one hundred twenty-four million, four hundred one thousand, three hundred seventeen".