Base | Representation |
---|---|
bin | 11101100101101010001111… |
… | …111000010000000100110001 |
3 | 122001202102201100021001210212 |
4 | 131211222033320100010301 |
5 | 114024032432223201001 |
6 | 1140433301544233505 |
7 | 36260451513032363 |
oct | 3545521770200461 |
9 | 561672640231725 |
10 | 130131333022001 |
11 | 3851142aa79533 |
12 | 127183a816b895 |
13 | 577c44168731c |
14 | 241c566702d33 |
15 | 100a0344717bb |
hex | 765a8fe10131 |
130131333022001 has 2 divisors, whose sum is σ = 130131333022002. Its totient is φ = 130131333022000.
The previous prime is 130131333021967. The next prime is 130131333022039. The reversal of 130131333022001 is 100220333131031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 114476839378225 + 15654493643776 = 10699385^2 + 3956576^2 .
It is a cyclic number.
It is not a de Polignac number, because 130131333022001 - 214 = 130131333005617 is a prime.
It is not a weakly prime, because it can be changed into another prime (130131333028001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65065666511000 + 65065666511001.
It is an arithmetic number, because the mean of its divisors is an integer number (65065666511001).
Almost surely, 2130131333022001 is an apocalyptic number.
It is an amenable number.
130131333022001 is a deficient number, since it is larger than the sum of its proper divisors (1).
130131333022001 is an equidigital number, since it uses as much as digits as its factorization.
130131333022001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 23.
Adding to 130131333022001 its reverse (100220333131031), we get a palindrome (230351666153032).
The spelling of 130131333022001 in words is "one hundred thirty trillion, one hundred thirty-one billion, three hundred thirty-three million, twenty-two thousand, one".
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