Base | Representation |
---|---|
bin | 11101100101101010110111… |
… | …110100000001001100010111 |
3 | 122001202111110000221112100222 |
4 | 131211222313310001030113 |
5 | 114024040320232013421 |
6 | 1140433452240224555 |
7 | 36260504226540266 |
oct | 3545526764011427 |
9 | 561674400845328 |
10 | 130132003001111 |
11 | 38511744183781 |
12 | 1271855460b15b |
13 | 577c51a415077 |
14 | 241c5cb6a45dd |
15 | 100a0731b3cab |
hex | 765ab7d01317 |
130132003001111 has 2 divisors, whose sum is σ = 130132003001112. Its totient is φ = 130132003001110.
The previous prime is 130132003001107. The next prime is 130132003001123. The reversal of 130132003001111 is 111100300231031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 130132003001111 - 22 = 130132003001107 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 130132003001111.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130132003001171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65066001500555 + 65066001500556.
It is an arithmetic number, because the mean of its divisors is an integer number (65066001500556).
Almost surely, 2130132003001111 is an apocalyptic number.
130132003001111 is a deficient number, since it is larger than the sum of its proper divisors (1).
130132003001111 is an equidigital number, since it uses as much as digits as its factorization.
130132003001111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 130132003001111 its reverse (111100300231031), we get a palindrome (241232303232142).
The spelling of 130132003001111 in words is "one hundred thirty trillion, one hundred thirty-two billion, three million, one thousand, one hundred eleven".
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