Base | Representation |
---|---|
bin | 1011110101011110000010… |
… | …0011001010000110100111 |
3 | 1201002001101220101100110001 |
4 | 2331113200203022012213 |
5 | 3201202040123034031 |
6 | 43402105304442131 |
7 | 2512113542366545 |
oct | 275274043120647 |
9 | 51061356340401 |
10 | 13013223252391 |
11 | 41679712a9a5a |
12 | 1562072179347 |
13 | 7351ac39600b |
14 | 32dbb42a6d95 |
15 | 1787854d7861 |
hex | bd5e08ca1a7 |
13013223252391 has 2 divisors, whose sum is σ = 13013223252392. Its totient is φ = 13013223252390.
The previous prime is 13013223252377. The next prime is 13013223252401. The reversal of 13013223252391 is 19325232231031.
13013223252391 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13013223252391 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13013223252391.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13013223252331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6506611626195 + 6506611626196.
It is an arithmetic number, because the mean of its divisors is an integer number (6506611626196).
Almost surely, 213013223252391 is an apocalyptic number.
13013223252391 is a deficient number, since it is larger than the sum of its proper divisors (1).
13013223252391 is an equidigital number, since it uses as much as digits as its factorization.
13013223252391 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 58320, while the sum is 37.
The spelling of 13013223252391 in words is "thirteen trillion, thirteen billion, two hundred twenty-three million, two hundred fifty-two thousand, three hundred ninety-one".
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