Base | Representation |
---|---|
bin | 111100100110010001… |
… | …1001100001000110011 |
3 | 110102220012210012101012 |
4 | 1321030203030020303 |
5 | 4113003111441201 |
6 | 135441000301135 |
7 | 12254552621141 |
oct | 1711443141063 |
9 | 412805705335 |
10 | 130133312051 |
11 | 50209953486 |
12 | 212794717ab |
13 | c36b6ac9c2 |
14 | 642708c591 |
15 | 35b98e85bb |
hex | 1e4c8cc233 |
130133312051 has 2 divisors, whose sum is σ = 130133312052. Its totient is φ = 130133312050.
The previous prime is 130133312027. The next prime is 130133312107. The reversal of 130133312051 is 150213331031.
It is a weak prime.
It is an emirp because it is prime and its reverse (150213331031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 130133312051 - 234 = 112953442867 is a prime.
It is not a weakly prime, because it can be changed into another prime (130133312011) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65066656025 + 65066656026.
It is an arithmetic number, because the mean of its divisors is an integer number (65066656026).
Almost surely, 2130133312051 is an apocalyptic number.
130133312051 is a deficient number, since it is larger than the sum of its proper divisors (1).
130133312051 is an equidigital number, since it uses as much as digits as its factorization.
130133312051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 810, while the sum is 23.
Adding to 130133312051 its reverse (150213331031), we get a palindrome (280346643082).
The spelling of 130133312051 in words is "one hundred thirty billion, one hundred thirty-three million, three hundred twelve thousand, fifty-one".
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