130133314019 has 2 divisors, whose sum is σ = 130133314020. Its totient is φ = 130133314018.

The previous prime is 130133314007. The next prime is 130133314021. The reversal of 130133314019 is 910413331031.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 130133314019 - 2³² = 125838346723 is a prime.

It is a super-2 number, since 2×130133314019² (a number of 23 digits) contains 22 as substring.

Together with 130133314021, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 130133313982 and 130133314000.

It is not a weakly prime, because it can be changed into another prime (130133314919) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65066657009 + 65066657010.

It is an arithmetic number, because the mean of its divisors is an integer number (65066657010).

Almost surely, 2^130133314019 is an apocalyptic number.

130133314019 is a deficient number, since it is larger than the sum of its proper divisors (1).

130133314019 is an equidigital number, since it uses as much as digits as its factorization.

130133314019 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2916, while the sum is 29.

The spelling of 130133314019 in words is "one hundred thirty billion, one hundred thirty-three million, three hundred fourteen thousand, nineteen".