Base | Representation |
---|---|
bin | 11101100101101100000110… |
… | …100000010000110001010111 |
3 | 122001202121212001011201002202 |
4 | 131211230012200100301113 |
5 | 114024101021221101403 |
6 | 1140434231241155115 |
7 | 36260552030330135 |
oct | 3545540640206127 |
9 | 561677761151082 |
10 | 130133323222103 |
11 | 38512261432303 |
12 | 1271886278ba9b |
13 | 577c69aaacc16 |
14 | 241c6b4b6a755 |
15 | 100a0ee04a688 |
hex | 765b06810c57 |
130133323222103 has 2 divisors, whose sum is σ = 130133323222104. Its totient is φ = 130133323222102.
The previous prime is 130133323222081. The next prime is 130133323222121. The reversal of 130133323222103 is 301222323331031.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-130133323222103 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130133323222163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65066661611051 + 65066661611052.
It is an arithmetic number, because the mean of its divisors is an integer number (65066661611052).
Almost surely, 2130133323222103 is an apocalyptic number.
130133323222103 is a deficient number, since it is larger than the sum of its proper divisors (1).
130133323222103 is an equidigital number, since it uses as much as digits as its factorization.
130133323222103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11664, while the sum is 29.
Adding to 130133323222103 its reverse (301222323331031), we get a palindrome (431355646553134).
The spelling of 130133323222103 in words is "one hundred thirty trillion, one hundred thirty-three billion, three hundred twenty-three million, two hundred twenty-two thousand, one hundred three".
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