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130140133310 = 25111183092121
BaseRepresentation
bin111100100110011110…
…1001101011110111110
3110102220200121202101102
41321030331031132332
54113011333231220
6135441402413102
712254664611165
oct1711475153676
9412820552342
10130140133310
1150212792390
122127b801192
13c36cc2a755
146427d463dc
1535ba2e4775
hex1e4cf4d7be

130140133310 has 16 divisors (see below), whose sum is σ = 255547898352. Its totient is φ = 47323684800.

The previous prime is 130140133309. The next prime is 130140133339. The reversal of 130140133310 is 13331041031.

130140133310 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a super-2 number, since 2×1301401333102 (a number of 23 digits) contains 22 as substring.

It is a Curzon number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 591545951 + ... + 591546170.

It is an arithmetic number, because the mean of its divisors is an integer number (15971743647).

Almost surely, 2130140133310 is an apocalyptic number.

130140133310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

130140133310 is a deficient number, since it is larger than the sum of its proper divisors (125407765042).

130140133310 is a wasteful number, since it uses less digits than its factorization.

130140133310 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1183092139.

The product of its (nonzero) digits is 324, while the sum is 20.

Adding to 130140133310 its reverse (13331041031), we get a palindrome (143471174341).

The spelling of 130140133310 in words is "one hundred thirty billion, one hundred forty million, one hundred thirty-three thousand, three hundred ten".

Divisors: 1 2 5 10 11 22 55 110 1183092121 2366184242 5915460605 11830921210 13014013331 26028026662 65070066655 130140133310