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13014025154477 is a prime number
BaseRepresentation
bin1011110101100001000001…
…0110001010111110101101
31201002010110210022012022022
42331120100112022332231
53201210210414420402
643402321032155525
72512142450424524
oct275302026127655
951063423265268
1013014025154477
114168242a19956
121562256838ba5
137352a95638a9
1432dc4c9a94bb
151787d0ad82a2
hexbd61058afad

13014025154477 has 2 divisors, whose sum is σ = 13014025154478. Its totient is φ = 13014025154476.

The previous prime is 13014025154453. The next prime is 13014025154509. The reversal of 13014025154477 is 77445152041031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7458038745481 + 5555986408996 = 2730941^2 + 2357114^2 .

It is a cyclic number.

It is not a de Polignac number, because 13014025154477 - 212 = 13014025150381 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13014025154437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6507012577238 + 6507012577239.

It is an arithmetic number, because the mean of its divisors is an integer number (6507012577239).

Almost surely, 213014025154477 is an apocalyptic number.

It is an amenable number.

13014025154477 is a deficient number, since it is larger than the sum of its proper divisors (1).

13014025154477 is an equidigital number, since it uses as much as digits as its factorization.

13014025154477 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 470400, while the sum is 44.

The spelling of 13014025154477 in words is "thirteen trillion, fourteen billion, twenty-five million, one hundred fifty-four thousand, four hundred seventy-seven".