Base | Representation |
---|---|
bin | 111100100110100000… |
… | …1100110011010001101 |
3 | 110102220202210012210212 |
4 | 1321031001212122031 |
5 | 4113012132041411 |
6 | 135441443212205 |
7 | 12255010443002 |
oct | 1711501463215 |
9 | 412822705725 |
10 | 130141283981 |
11 | 502133a8955 |
12 | 21280077065 |
13 | c370241417 |
14 | 64281658a9 |
15 | 35ba47068b |
hex | 1e4d06668d |
130141283981 has 2 divisors, whose sum is σ = 130141283982. Its totient is φ = 130141283980.
The previous prime is 130141283971. The next prime is 130141284041. The reversal of 130141283981 is 189382141031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 124136428900 + 6004855081 = 352330^2 + 77491^2 .
It is a cyclic number.
It is not a de Polignac number, because 130141283981 - 26 = 130141283917 is a prime.
It is a super-2 number, since 2×1301412839812 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130141283971) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65070641990 + 65070641991.
It is an arithmetic number, because the mean of its divisors is an integer number (65070641991).
Almost surely, 2130141283981 is an apocalyptic number.
It is an amenable number.
130141283981 is a deficient number, since it is larger than the sum of its proper divisors (1).
130141283981 is an equidigital number, since it uses as much as digits as its factorization.
130141283981 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 41472, while the sum is 41.
The spelling of 130141283981 in words is "one hundred thirty billion, one hundred forty-one million, two hundred eighty-three thousand, nine hundred eighty-one".
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