Base | Representation |
---|---|
bin | 11000001111011010… |
… | …01111011100001001 |
3 | 1020120222111222002222 |
4 | 30013231033130021 |
5 | 203123113431441 |
6 | 5551215303425 |
7 | 640334615144 |
oct | 140755173411 |
9 | 36528458088 |
10 | 13014202121 |
11 | 55791a5748 |
12 | 263251ab75 |
13 | 12c530511b |
14 | 8b65c505b |
15 | 512809d4b |
hex | 307b4f709 |
13014202121 has 2 divisors, whose sum is σ = 13014202122. Its totient is φ = 13014202120.
The previous prime is 13014202087. The next prime is 13014202127. The reversal of 13014202121 is 12120241031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12969793225 + 44408896 = 113885^2 + 6664^2 .
It is an emirp because it is prime and its reverse (12120241031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13014202121 - 222 = 13010007817 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13014202121.
It is not a weakly prime, because it can be changed into another prime (13014202127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6507101060 + 6507101061.
It is an arithmetic number, because the mean of its divisors is an integer number (6507101061).
Almost surely, 213014202121 is an apocalyptic number.
It is an amenable number.
13014202121 is a deficient number, since it is larger than the sum of its proper divisors (1).
13014202121 is an equidigital number, since it uses as much as digits as its factorization.
13014202121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 17.
Adding to 13014202121 its reverse (12120241031), we get a palindrome (25134443152).
The spelling of 13014202121 in words is "thirteen billion, fourteen million, two hundred two thousand, one hundred twenty-one".
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