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13014304241 is a prime number
BaseRepresentation
bin11000001111011011…
…01000010111110001
31020120222201011012012
430013231220113301
5203123130213431
65551221412305
7640335521651
oct140755502761
936528634165
1013014304241
115579265444
12263256a095
1312c533c753
148b6610361
1551282a22b
hex307b685f1

13014304241 has 2 divisors, whose sum is σ = 13014304242. Its totient is φ = 13014304240.

The previous prime is 13014304211. The next prime is 13014304243. The reversal of 13014304241 is 14240341031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12223513600 + 790790641 = 110560^2 + 28121^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13014304241 is a prime.

It is a super-2 number, since 2×130143042412 (a number of 21 digits) contains 22 as substring.

Together with 13014304243, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13014304243) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6507152120 + 6507152121.

It is an arithmetic number, because the mean of its divisors is an integer number (6507152121).

Almost surely, 213014304241 is an apocalyptic number.

It is an amenable number.

13014304241 is a deficient number, since it is larger than the sum of its proper divisors (1).

13014304241 is an equidigital number, since it uses as much as digits as its factorization.

13014304241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 13014304241 its reverse (14240341031), we get a palindrome (27254645272).

The spelling of 13014304241 in words is "thirteen billion, fourteen million, three hundred four thousand, two hundred forty-one".