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130143334001 is a prime number
BaseRepresentation
bin111100100110100100…
…1011010111001110001
3110102220220122100220112
41321031021122321301
54113013143142001
6135441555151105
712255034041512
oct1711511327161
9412826570815
10130143334001
115021457908a
12212808a5495
13c3707ab555
14642853aa09
1535ba727cbb
hex1e4d25ae71

130143334001 has 2 divisors, whose sum is σ = 130143334002. Its totient is φ = 130143334000.

The previous prime is 130143333979. The next prime is 130143334003. The reversal of 130143334001 is 100433341031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 129635282401 + 508051600 = 360049^2 + 22540^2 .

It is a cyclic number.

It is not a de Polignac number, because 130143334001 - 214 = 130143317617 is a prime.

It is a Sophie Germain prime.

Together with 130143334003, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (130143334003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65071667000 + 65071667001.

It is an arithmetic number, because the mean of its divisors is an integer number (65071667001).

Almost surely, 2130143334001 is an apocalyptic number.

It is an amenable number.

130143334001 is a deficient number, since it is larger than the sum of its proper divisors (1).

130143334001 is an equidigital number, since it uses as much as digits as its factorization.

130143334001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 130143334001 its reverse (100433341031), we get a palindrome (230576675032).

The spelling of 130143334001 in words is "one hundred thirty billion, one hundred forty-three million, three hundred thirty-four thousand, one".