Base | Representation |
---|---|
bin | 11101100101110110001011… |
… | …011011010111101101101111 |
3 | 122001210122210002221202222210 |
4 | 131211312023123113231233 |
5 | 114024240201132303033 |
6 | 1140443221035541503 |
7 | 36261414123105660 |
oct | 3545661333275557 |
9 | 561718702852883 |
10 | 130144143244143 |
11 | 38516904012a86 |
12 | 1271a9822ba893 |
13 | 5780703640722 |
14 | 241d01db8b367 |
15 | 100a533dd7d63 |
hex | 765d8b6d7b6f |
130144143244143 has 32 divisors (see below), whose sum is σ = 203014290166272. Its totient is φ = 72619105104000.
The previous prime is 130144143244111. The next prime is 130144143244183. The reversal of 130144143244143 is 341442341441031.
It is not a de Polignac number, because 130144143244143 - 25 = 130144143244111 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130144143244183) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 276852708 + ... + 277322393.
It is an arithmetic number, because the mean of its divisors is an integer number (6344196567696).
Almost surely, 2130144143244143 is an apocalyptic number.
130144143244143 is a deficient number, since it is larger than the sum of its proper divisors (72870146922129).
130144143244143 is a wasteful number, since it uses less digits than its factorization.
130144143244143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 554175375.
The product of its (nonzero) digits is 221184, while the sum is 39.
Adding to 130144143244143 its reverse (341442341441031), we get a palindrome (471586484685174).
The spelling of 130144143244143 in words is "one hundred thirty trillion, one hundred forty-four billion, one hundred forty-three million, two hundred forty-four thousand, one hundred forty-three".
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