Base | Representation |
---|---|
bin | 10010111100000100011… |
… | …111011001101010110011 |
3 | 11121102021022120222201120 |
4 | 102330010133121222303 |
5 | 132310332302244110 |
6 | 2433513355233323 |
7 | 163012104065550 |
oct | 22740437315263 |
9 | 4542238528646 |
10 | 1301450431155 |
11 | 461a3a926626 |
12 | 190291148843 |
13 | 95959752624 |
14 | 46dc2067a27 |
15 | 23cc142c870 |
hex | 12f047d9ab3 |
1301450431155 has 32 divisors (see below), whose sum is σ = 2519783023104. Its totient is φ = 559951781376.
The previous prime is 1301450431139. The next prime is 1301450431157. The reversal of 1301450431155 is 5511340541031.
It is a happy number.
It is not a de Polignac number, because 1301450431155 - 24 = 1301450431139 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1301450431157) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 364550157 + ... + 364553726.
It is an arithmetic number, because the mean of its divisors is an integer number (78743219472).
Almost surely, 21301450431155 is an apocalyptic number.
1301450431155 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1301450431155 is a deficient number, since it is larger than the sum of its proper divisors (1218332591949).
1301450431155 is a wasteful number, since it uses less digits than its factorization.
1301450431155 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 729103915.
The product of its (nonzero) digits is 18000, while the sum is 33.
Adding to 1301450431155 its reverse (5511340541031), we get a palindrome (6812790972186).
The spelling of 1301450431155 in words is "one trillion, three hundred one billion, four hundred fifty million, four hundred thirty-one thousand, one hundred fifty-five".
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