Base | Representation |
---|---|
bin | 10010111100000100101… |
… | …110110000001000101101 |
3 | 11121102021121011102212111 |
4 | 102330010232300020231 |
5 | 132310334320032331 |
6 | 2433514021404021 |
7 | 163012153226065 |
oct | 22740456601055 |
9 | 4542247142774 |
10 | 1301454455341 |
11 | 461a42124aa7 |
12 | 190292569611 |
13 | 9595a5311c1 |
14 | 46dc27d43a5 |
15 | 23cc1974db1 |
hex | 12f04bb022d |
1301454455341 has 2 divisors, whose sum is σ = 1301454455342. Its totient is φ = 1301454455340.
The previous prime is 1301454455239. The next prime is 1301454455351. The reversal of 1301454455341 is 1435544541031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1281924392841 + 19530062500 = 1132221^2 + 139750^2 .
It is a cyclic number.
It is not a de Polignac number, because 1301454455341 - 225 = 1301420900909 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1301454455294 and 1301454455303.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1301454455351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650727227670 + 650727227671.
It is an arithmetic number, because the mean of its divisors is an integer number (650727227671).
Almost surely, 21301454455341 is an apocalyptic number.
It is an amenable number.
1301454455341 is a deficient number, since it is larger than the sum of its proper divisors (1).
1301454455341 is an equidigital number, since it uses as much as digits as its factorization.
1301454455341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 288000, while the sum is 40.
Adding to 1301454455341 its reverse (1435544541031), we get a palindrome (2736998996372).
The spelling of 1301454455341 in words is "one trillion, three hundred one billion, four hundred fifty-four million, four hundred fifty-five thousand, three hundred forty-one".
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