Base | Representation |
---|---|
bin | 11000001111101010… |
… | …00001111110011001 |
3 | 1020121010100201012121 |
4 | 30013311001332121 |
5 | 203124124302441 |
6 | 5551331141241 |
7 | 640361151406 |
oct | 140765017631 |
9 | 36533321177 |
10 | 13016244121 |
11 | 557a36a951 |
12 | 2633144821 |
13 | 12c586b6ca |
14 | 8b69972ad |
15 | 512aaedd1 |
hex | 307d41f99 |
13016244121 has 2 divisors, whose sum is σ = 13016244122. Its totient is φ = 13016244120.
The previous prime is 13016244079. The next prime is 13016244149. The reversal of 13016244121 is 12144261031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11377208896 + 1639035225 = 106664^2 + 40485^2 .
It is a cyclic number.
It is not a de Polignac number, because 13016244121 - 29 = 13016243609 is a prime.
It is a super-2 number, since 2×130162441212 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13016244161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6508122060 + 6508122061.
It is an arithmetic number, because the mean of its divisors is an integer number (6508122061).
Almost surely, 213016244121 is an apocalyptic number.
It is an amenable number.
13016244121 is a deficient number, since it is larger than the sum of its proper divisors (1).
13016244121 is an equidigital number, since it uses as much as digits as its factorization.
13016244121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 25.
The spelling of 13016244121 in words is "thirteen billion, sixteen million, two hundred forty-four thousand, one hundred twenty-one".
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