Base | Representation |
---|---|
bin | 111100100111100101… |
… | …1111010100111110011 |
3 | 110110000022000100100021 |
4 | 1321033023322213303 |
5 | 4113100422331033 |
6 | 135445220304311 |
7 | 12255630566251 |
oct | 1711713724763 |
9 | 413008010307 |
10 | 130177542643 |
11 | 50231913595 |
12 | 21290242097 |
13 | c3778c8055 |
14 | 642ccc35d1 |
15 | 35bd733b2d |
hex | 1e4f2fa9f3 |
130177542643 has 2 divisors, whose sum is σ = 130177542644. Its totient is φ = 130177542642.
The previous prime is 130177542641. The next prime is 130177542679. The reversal of 130177542643 is 346245771031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 130177542643 - 21 = 130177542641 is a prime.
Together with 130177542641, it forms a pair of twin primes.
It is a self number, because there is not a number n which added to its sum of digits gives 130177542643.
It is not a weakly prime, because it can be changed into another prime (130177542641) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65088771321 + 65088771322.
It is an arithmetic number, because the mean of its divisors is an integer number (65088771322).
Almost surely, 2130177542643 is an apocalyptic number.
130177542643 is a deficient number, since it is larger than the sum of its proper divisors (1).
130177542643 is an equidigital number, since it uses as much as digits as its factorization.
130177542643 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 423360, while the sum is 43.
The spelling of 130177542643 in words is "one hundred thirty billion, one hundred seventy-seven million, five hundred forty-two thousand, six hundred forty-three".
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