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130200000030019 is a prime number
BaseRepresentation
bin11101100110101010001100…
…110000000110010101000011
3122001222222221212100111110001
4131212222030300012111003
5114031144100001430034
61140525015420420431
736265432243002133
oct3546521460062503
9561888855314401
10130200000030019
1138538567789a37
12127297706a7717
135785a658b4c0a
1424219dc28aac3
15100bc02a26a14
hex766a8cc06543

130200000030019 has 2 divisors, whose sum is σ = 130200000030020. Its totient is φ = 130200000030018.

The previous prime is 130200000030017. The next prime is 130200000030053. The reversal of 130200000030019 is 910030000002031.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 130200000030019 - 21 = 130200000030017 is a prime.

It is a super-2 number, since 2×1302000000300192 (a number of 29 digits) contains 22 as substring.

Together with 130200000030017, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 130200000029978 and 130200000030005.

It is not a weakly prime, because it can be changed into another prime (130200000030017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65100000015009 + 65100000015010.

It is an arithmetic number, because the mean of its divisors is an integer number (65100000015010).

Almost surely, 2130200000030019 is an apocalyptic number.

130200000030019 is a deficient number, since it is larger than the sum of its proper divisors (1).

130200000030019 is an equidigital number, since it uses as much as digits as its factorization.

130200000030019 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 162, while the sum is 19.

The spelling of 130200000030019 in words is "one hundred thirty trillion, two hundred billion, thirty thousand, nineteen".