Base | Representation |
---|---|
bin | 11101100110101010011001… |
… | …011001001000011011100011 |
3 | 122002000000111122102102202211 |
4 | 131212222121121020123203 |
5 | 114031200013300104443 |
6 | 1140525052434222551 |
7 | 36265440426453205 |
oct | 3546523131103343 |
9 | 562000448372684 |
10 | 130200212113123 |
11 | 38538666475129 |
12 | 1272980b724a57 |
13 | 5785a9a80cc89 |
14 | 2421a1c4d6775 |
15 | 100bc1646b19d |
hex | 766a996486e3 |
130200212113123 has 2 divisors, whose sum is σ = 130200212113124. Its totient is φ = 130200212113122.
The previous prime is 130200212113099. The next prime is 130200212113133. The reversal of 130200212113123 is 321311212002031.
It is a strong prime.
It is an emirp because it is prime and its reverse (321311212002031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 130200212113123 - 233 = 130191622178531 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 130200212113094 and 130200212113103.
It is not a weakly prime, because it can be changed into another prime (130200212113133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65100106056561 + 65100106056562.
It is an arithmetic number, because the mean of its divisors is an integer number (65100106056562).
Almost surely, 2130200212113123 is an apocalyptic number.
130200212113123 is a deficient number, since it is larger than the sum of its proper divisors (1).
130200212113123 is an equidigital number, since it uses as much as digits as its factorization.
130200212113123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 130200212113123 its reverse (321311212002031), we get a palindrome (451511424115154).
The spelling of 130200212113123 in words is "one hundred thirty trillion, two hundred billion, two hundred twelve million, one hundred thirteen thousand, one hundred twenty-three".
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