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130200212113123 is a prime number
BaseRepresentation
bin11101100110101010011001…
…011001001000011011100011
3122002000000111122102102202211
4131212222121121020123203
5114031200013300104443
61140525052434222551
736265440426453205
oct3546523131103343
9562000448372684
10130200212113123
1138538666475129
121272980b724a57
135785a9a80cc89
142421a1c4d6775
15100bc1646b19d
hex766a996486e3

130200212113123 has 2 divisors, whose sum is σ = 130200212113124. Its totient is φ = 130200212113122.

The previous prime is 130200212113099. The next prime is 130200212113133. The reversal of 130200212113123 is 321311212002031.

It is a strong prime.

It is an emirp because it is prime and its reverse (321311212002031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 130200212113123 - 233 = 130191622178531 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 130200212113094 and 130200212113103.

It is not a weakly prime, because it can be changed into another prime (130200212113133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65100106056561 + 65100106056562.

It is an arithmetic number, because the mean of its divisors is an integer number (65100106056562).

Almost surely, 2130200212113123 is an apocalyptic number.

130200212113123 is a deficient number, since it is larger than the sum of its proper divisors (1).

130200212113123 is an equidigital number, since it uses as much as digits as its factorization.

130200212113123 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 130200212113123 its reverse (321311212002031), we get a palindrome (451511424115154).

The spelling of 130200212113123 in words is "one hundred thirty trillion, two hundred billion, two hundred twelve million, one hundred thirteen thousand, one hundred twenty-three".