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130200212113133 is a prime number
BaseRepresentation
bin11101100110101010011001…
…011001001000011011101101
3122002000000111122102102210012
4131212222121121020123231
5114031200013300110013
61140525052434223005
736265440426453221
oct3546523131103355
9562000448372705
10130200212113133
1138538666475138
121272980b724a65
135785a9a80cc96
142421a1c4d6781
15100bc1646b1a8
hex766a996486ed

130200212113133 has 2 divisors, whose sum is σ = 130200212113134. Its totient is φ = 130200212113132.

The previous prime is 130200212113123. The next prime is 130200212113151. The reversal of 130200212113133 is 331311212002031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 129275149025929 + 925063087204 = 11369923^2 + 961802^2 .

It is a cyclic number.

It is not a de Polignac number, because 130200212113133 - 220 = 130200211064557 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 130200212113099 and 130200212113108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130200212113123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65100106056566 + 65100106056567.

It is an arithmetic number, because the mean of its divisors is an integer number (65100106056567).

Almost surely, 2130200212113133 is an apocalyptic number.

It is an amenable number.

130200212113133 is a deficient number, since it is larger than the sum of its proper divisors (1).

130200212113133 is an equidigital number, since it uses as much as digits as its factorization.

130200212113133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 130200212113133 its reverse (331311212002031), we get a palindrome (461511424115164).

The spelling of 130200212113133 in words is "one hundred thirty trillion, two hundred billion, two hundred twelve million, one hundred thirteen thousand, one hundred thirty-three".