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13020114103 is a prime number
BaseRepresentation
bin11000010000000111…
…10010110010110111
31020121101122022211021
430020003302302313
5203131122122403
65551550122011
7640436100223
oct141003626267
936541568737
1013020114103
115581573487
1226344b0307
1312c65c5039
148b72c3783
155130c68bd
hex3080f2cb7

13020114103 has 2 divisors, whose sum is σ = 13020114104. Its totient is φ = 13020114102.

The previous prime is 13020114067. The next prime is 13020114127. The reversal of 13020114103 is 30141102031.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13020114103 - 225 = 12986559671 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13020114703) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6510057051 + 6510057052.

It is an arithmetic number, because the mean of its divisors is an integer number (6510057052).

Almost surely, 213020114103 is an apocalyptic number.

13020114103 is a deficient number, since it is larger than the sum of its proper divisors (1).

13020114103 is an equidigital number, since it uses as much as digits as its factorization.

13020114103 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 13020114103 its reverse (30141102031), we get a palindrome (43161216134).

The spelling of 13020114103 in words is "thirteen billion, twenty million, one hundred fourteen thousand, one hundred three".