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1302012100997 is a prime number
BaseRepresentation
bin10010111100100101111…
…110000000000110000101
311121110201110110202220022
4102330211332000012011
5132313010044212442
62434045221544525
7163032034153136
oct22744576000605
94543643422808
101302012100997
114621a8984483
12190409275145
1395a18c1a74a
14470368b3c8d
1523d058c83d2
hex12f25f80185

1302012100997 has 2 divisors, whose sum is σ = 1302012100998. Its totient is φ = 1302012100996.

The previous prime is 1302012100993. The next prime is 1302012101003. The reversal of 1302012100997 is 7990012102031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1009142802721 + 292869298276 = 1004561^2 + 541174^2 .

It is an emirp because it is prime and its reverse (7990012102031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1302012100997 - 22 = 1302012100993 is a prime.

It is a super-2 number, since 2×13020121009972 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1302012100993) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651006050498 + 651006050499.

It is an arithmetic number, because the mean of its divisors is an integer number (651006050499).

Almost surely, 21302012100997 is an apocalyptic number.

It is an amenable number.

1302012100997 is a deficient number, since it is larger than the sum of its proper divisors (1).

1302012100997 is an equidigital number, since it uses as much as digits as its factorization.

1302012100997 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6804, while the sum is 35.

The spelling of 1302012100997 in words is "one trillion, three hundred two billion, twelve million, one hundred thousand, nine hundred ninety-seven".