Base | Representation |
---|---|
bin | 111100101000010011… |
… | …0001100110111001111 |
3 | 110110001221112210021212 |
4 | 1321100212030313033 |
5 | 4113123002212234 |
6 | 135451423445035 |
7 | 12256336012235 |
oct | 1712046146717 |
9 | 413057483255 |
10 | 130201210319 |
11 | 50244209454 |
12 | 2129815677b |
13 | c37c7939ab |
14 | 64320c4955 |
15 | 35c085b5ce |
hex | 1e5098cdcf |
130201210319 has 2 divisors, whose sum is σ = 130201210320. Its totient is φ = 130201210318.
The previous prime is 130201210247. The next prime is 130201210367. The reversal of 130201210319 is 913012102031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130201210319 - 224 = 130184433103 is a prime.
It is a super-4 number, since 4×1302012103194 (a number of 46 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 130201210294 and 130201210303.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130201210379) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65100605159 + 65100605160.
It is an arithmetic number, because the mean of its divisors is an integer number (65100605160).
Almost surely, 2130201210319 is an apocalyptic number.
130201210319 is a deficient number, since it is larger than the sum of its proper divisors (1).
130201210319 is an equidigital number, since it uses as much as digits as its factorization.
130201210319 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 23.
The spelling of 130201210319 in words is "one hundred thirty billion, two hundred one million, two hundred ten thousand, three hundred nineteen".
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