Base | Representation |
---|---|
bin | 10010111100100101111… |
… | …110011000010000001101 |
3 | 11121110201110122210122012 |
4 | 102330211332120100031 |
5 | 132313010110344244 |
6 | 2434045224031005 |
7 | 163032035044466 |
oct | 22744576302015 |
9 | 4543643583565 |
10 | 1302012199949 |
11 | 4621a8a4185a |
12 | 190409302465 |
13 | 95a18c537b6 |
14 | 470368dbd6d |
15 | 23d058e789e |
hex | 12f25f9840d |
1302012199949 has 2 divisors, whose sum is σ = 1302012199950. Its totient is φ = 1302012199948.
The previous prime is 1302012199933. The next prime is 1302012200023. The reversal of 1302012199949 is 9499912102031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1290780015625 + 11232184324 = 1136125^2 + 105982^2 .
It is a cyclic number.
It is not a de Polignac number, because 1302012199949 - 24 = 1302012199933 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1302012199897 and 1302012199906.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1302012189949) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651006099974 + 651006099975.
It is an arithmetic number, because the mean of its divisors is an integer number (651006099975).
Almost surely, 21302012199949 is an apocalyptic number.
It is an amenable number.
1302012199949 is a deficient number, since it is larger than the sum of its proper divisors (1).
1302012199949 is an equidigital number, since it uses as much as digits as its factorization.
1302012199949 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 314928, while the sum is 50.
The spelling of 1302012199949 in words is "one trillion, three hundred two billion, twelve million, one hundred ninety-nine thousand, nine hundred forty-nine".
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