Base | Representation |
---|---|
bin | 1011110101110111110000… |
… | …1110010110110001000111 |
3 | 1201002201020020200002210001 |
4 | 2331131330032112301013 |
5 | 3201310211240342411 |
6 | 43405210512342131 |
7 | 2512446650026606 |
oct | 275357416266107 |
9 | 51081206602701 |
10 | 13020130012231 |
11 | 416a895a59941 |
12 | 156347b244947 |
13 | 735a40284264 |
14 | 33026b6b1a3d |
15 | 178a3ba34dc1 |
hex | bd77c396c47 |
13020130012231 has 2 divisors, whose sum is σ = 13020130012232. Its totient is φ = 13020130012230.
The previous prime is 13020130012177. The next prime is 13020130012271. The reversal of 13020130012231 is 13221003102031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13020130012231 - 215 = 13020129979463 is a prime.
It is a super-2 number, since 2×130201300122312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13020130012199 and 13020130012208.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13020130012271) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6510065006115 + 6510065006116.
It is an arithmetic number, because the mean of its divisors is an integer number (6510065006116).
Almost surely, 213020130012231 is an apocalyptic number.
13020130012231 is a deficient number, since it is larger than the sum of its proper divisors (1).
13020130012231 is an equidigital number, since it uses as much as digits as its factorization.
13020130012231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 13020130012231 its reverse (13221003102031), we get a palindrome (26241133114262).
The spelling of 13020130012231 in words is "thirteen trillion, twenty billion, one hundred thirty million, twelve thousand, two hundred thirty-one".
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