Base | Representation |
---|---|
bin | 11101100110101011011100… |
… | …000110001010011110001111 |
3 | 122002000010101122012122212201 |
4 | 131212223130012022132033 |
5 | 114031204311242323343 |
6 | 1140525355452342331 |
7 | 36265510235612503 |
oct | 3546533406123617 |
9 | 562003348178781 |
10 | 130201331214223 |
11 | 38539090146375 |
12 | 12729a824749a7 |
13 | 5785c1861ab89 |
14 | 2421ac6da8303 |
15 | 100bc7e82694d |
hex | 766adc18a78f |
130201331214223 has 2 divisors, whose sum is σ = 130201331214224. Its totient is φ = 130201331214222.
The previous prime is 130201331214109. The next prime is 130201331214247. The reversal of 130201331214223 is 322412133102031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130201331214223 - 213 = 130201331206031 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 130201331214191 and 130201331214200.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130201331214263) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65100665607111 + 65100665607112.
It is an arithmetic number, because the mean of its divisors is an integer number (65100665607112).
Almost surely, 2130201331214223 is an apocalyptic number.
130201331214223 is a deficient number, since it is larger than the sum of its proper divisors (1).
130201331214223 is an equidigital number, since it uses as much as digits as its factorization.
130201331214223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 130201331214223 its reverse (322412133102031), we get a palindrome (452613464316254).
The spelling of 130201331214223 in words is "one hundred thirty trillion, two hundred one billion, three hundred thirty-one million, two hundred fourteen thousand, two hundred twenty-three".
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