Base | Representation |
---|---|
bin | 1011110101111000001001… |
… | …0000100001100101000110 |
3 | 1201002201111022011012210121 |
4 | 2331132002100201211012 |
5 | 3201310413144302402 |
6 | 43405224530212154 |
7 | 2512452316342345 |
oct | 275360220414506 |
9 | 51081438135717 |
10 | 13020231244102 |
11 | 416a938111945 |
12 | 15634a912405a |
13 | 735a58239684 |
14 | 33027ad03b5c |
15 | 178a4587e837 |
hex | bd782421946 |
13020231244102 has 4 divisors (see below), whose sum is σ = 19530346866156. Its totient is φ = 6510115622050.
The previous prime is 13020231244081. The next prime is 13020231244109. The reversal of 13020231244102 is 20144213202031.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13020231244109) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3255057811024 + ... + 3255057811027.
It is an arithmetic number, because the mean of its divisors is an integer number (4882586716539).
Almost surely, 213020231244102 is an apocalyptic number.
13020231244102 is a deficient number, since it is larger than the sum of its proper divisors (6510115622054).
13020231244102 is an equidigital number, since it uses as much as digits as its factorization.
13020231244102 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6510115622053.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 13020231244102 its reverse (20144213202031), we get a palindrome (33164444446133).
The spelling of 13020231244102 in words is "thirteen trillion, twenty billion, two hundred thirty-one million, two hundred forty-four thousand, one hundred two".
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