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130202313020233 is a prime number
BaseRepresentation
bin11101100110101100010110…
…100111011101001101001001
3122002000012221001122120112021
4131212230112213131031021
5114031213314113121413
61140530041124044441
736265543460045626
oct3546542647351511
9562005831576467
10130202313020233
11385395443727a3
121272a0b7233721
135786043b5798c
142421b7b53b34d
15100bcdab1218d
hex766b169dd349

130202313020233 has 2 divisors, whose sum is σ = 130202313020234. Its totient is φ = 130202313020232.

The previous prime is 130202313020113. The next prime is 130202313020261. The reversal of 130202313020233 is 332020313202031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 97131037938064 + 33071275082169 = 9855508^2 + 5750763^2 .

It is a cyclic number.

It is not a de Polignac number, because 130202313020233 - 217 = 130202312889161 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 130202313020198 and 130202313020207.

It is not a weakly prime, because it can be changed into another prime (130202313060233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65101156510116 + 65101156510117.

It is an arithmetic number, because the mean of its divisors is an integer number (65101156510117).

Almost surely, 2130202313020233 is an apocalyptic number.

It is an amenable number.

130202313020233 is a deficient number, since it is larger than the sum of its proper divisors (1).

130202313020233 is an equidigital number, since it uses as much as digits as its factorization.

130202313020233 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3888, while the sum is 25.

Adding to 130202313020233 its reverse (332020313202031), we get a palindrome (462222626222264).

The spelling of 130202313020233 in words is "one hundred thirty trillion, two hundred two billion, three hundred thirteen million, twenty thousand, two hundred thirty-three".