130204414003 has 2 divisors, whose sum is σ = 130204414004. Its totient is φ = 130204414002.

The previous prime is 130204414001. The next prime is 130204414027. The reversal of 130204414003 is 300414402031.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 130204414003 - 2¹ = 130204414001 is a prime.

Together with 130204414001, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (130204414001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65102207001 + 65102207002.

It is an arithmetic number, because the mean of its divisors is an integer number (65102207002).

Almost surely, 2^130204414003 is an apocalyptic number.

130204414003 is a deficient number, since it is larger than the sum of its proper divisors (1).

130204414003 is an equidigital number, since it uses as much as digits as its factorization.

130204414003 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 22.

Adding to 130204414003 its reverse (300414402031), we get a palindrome (430618816034).

The spelling of 130204414003 in words is "one hundred thirty billion, two hundred four million, four hundred fourteen thousand, three".