Base | Representation |
---|---|
bin | 1011110101111010000101… |
… | …1100110101111010111111 |
3 | 1201002202211202212202122111 |
4 | 2331132201130311322333 |
5 | 3201313001132114342 |
6 | 43405352502554451 |
7 | 2512501302454546 |
oct | 275364134657277 |
9 | 51082752782574 |
10 | 13020754566847 |
11 | 4170086558a85 |
12 | 1563614438a27 |
13 | 735b0c7993c1 |
14 | 3302ca60b15d |
15 | 178a767a3217 |
hex | bd7a1735ebf |
13020754566847 has 2 divisors, whose sum is σ = 13020754566848. Its totient is φ = 13020754566846.
The previous prime is 13020754566767. The next prime is 13020754566887. The reversal of 13020754566847 is 74866545702031.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13020754566847 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13020754566791 and 13020754566800.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13020754566887) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6510377283423 + 6510377283424.
It is an arithmetic number, because the mean of its divisors is an integer number (6510377283424).
Almost surely, 213020754566847 is an apocalyptic number.
13020754566847 is a deficient number, since it is larger than the sum of its proper divisors (1).
13020754566847 is an equidigital number, since it uses as much as digits as its factorization.
13020754566847 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 33868800, while the sum is 58.
The spelling of 13020754566847 in words is "thirteen trillion, twenty billion, seven hundred fifty-four million, five hundred sixty-six thousand, eight hundred forty-seven".
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