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1302100199977 is a prime number
BaseRepresentation
bin10010111100101011001…
…110000100101000101001
311121110221121020122222111
4102330223032010220221
5132313200122344402
62434102050122321
7163034154040363
oct22745316045051
94543847218874
101302100199977
11462243687555
121904328803a1
1395a31255315
1447044487d33
1523d0d4cb9d7
hex12f2b384a29

1302100199977 has 2 divisors, whose sum is σ = 1302100199978. Its totient is φ = 1302100199976.

The previous prime is 1302100199971. The next prime is 1302100200019. The reversal of 1302100199977 is 7799910012031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1183143500176 + 118956699801 = 1087724^2 + 344901^2 .

It is a cyclic number.

It is not a de Polignac number, because 1302100199977 - 23 = 1302100199969 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1302100199977.

It is not a weakly prime, because it can be changed into another prime (1302100199971) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651050099988 + 651050099989.

It is an arithmetic number, because the mean of its divisors is an integer number (651050099989).

Almost surely, 21302100199977 is an apocalyptic number.

It is an amenable number.

1302100199977 is a deficient number, since it is larger than the sum of its proper divisors (1).

1302100199977 is an equidigital number, since it uses as much as digits as its factorization.

1302100199977 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 214326, while the sum is 49.

The spelling of 1302100199977 in words is "one trillion, three hundred two billion, one hundred million, one hundred ninety-nine thousand, nine hundred seventy-seven".