Base | Representation |
---|---|
bin | 10010111100101011001… |
… | …110000100101001010011 |
3 | 11121110221121020200001001 |
4 | 102330223032010221103 |
5 | 132313200122400034 |
6 | 2434102050122431 |
7 | 163034154040453 |
oct | 22745316045123 |
9 | 4543847220031 |
10 | 1302100200019 |
11 | 462243687593 |
12 | 190432880417 |
13 | 95a31255348 |
14 | 47044487d63 |
15 | 23d0d4cba14 |
hex | 12f2b384a53 |
1302100200019 has 2 divisors, whose sum is σ = 1302100200020. Its totient is φ = 1302100200018.
The previous prime is 1302100199977. The next prime is 1302100200041. The reversal of 1302100200019 is 9100020012031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1302100200019 - 29 = 1302100199507 is a prime.
It is a super-2 number, since 2×13021002000192 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1302100199969 and 1302100200005.
It is not a weakly prime, because it can be changed into another prime (1302100201019) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651050100009 + 651050100010.
It is an arithmetic number, because the mean of its divisors is an integer number (651050100010).
Almost surely, 21302100200019 is an apocalyptic number.
1302100200019 is a deficient number, since it is larger than the sum of its proper divisors (1).
1302100200019 is an equidigital number, since it uses as much as digits as its factorization.
1302100200019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108, while the sum is 19.
The spelling of 1302100200019 in words is "one trillion, three hundred two billion, one hundred million, two hundred thousand, nineteen".
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