Base | Representation |
---|---|
bin | 11101100110110011100110… |
… | …110001101011111001100011 |
3 | 122002000222000202211220101121 |
4 | 131212303212301223321203 |
5 | 114031330241141030313 |
6 | 1140533405545113111 |
7 | 36266240446066114 |
oct | 3546634661537143 |
9 | 562028022756347 |
10 | 130210100330083 |
11 | 3854188007a964 |
12 | 1272b70b188797 |
13 | 57869b52bc627 |
14 | 24222b987c20b |
15 | 100c0e45e828d |
hex | 766ce6c6be63 |
130210100330083 has 2 divisors, whose sum is σ = 130210100330084. Its totient is φ = 130210100330082.
The previous prime is 130210100329951. The next prime is 130210100330087. The reversal of 130210100330083 is 380033001012031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130210100330083 - 213 = 130210100321891 is a prime.
It is not a weakly prime, because it can be changed into another prime (130210100330087) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65105050165041 + 65105050165042.
It is an arithmetic number, because the mean of its divisors is an integer number (65105050165042).
Almost surely, 2130210100330083 is an apocalyptic number.
130210100330083 is a deficient number, since it is larger than the sum of its proper divisors (1).
130210100330083 is an equidigital number, since it uses as much as digits as its factorization.
130210100330083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 25.
The spelling of 130210100330083 in words is "one hundred thirty trillion, two hundred ten billion, one hundred million, three hundred thirty thousand, eighty-three".
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